We need to evaluate the expression involving dot products and cross product of unit vectors.
Step 1: Recall the properties of unit vectors.
For the standard unit vectors \(\hat{i}, \hat{j}, \hat{k}\):
- \(\hat{i} \cdot \hat{i} = |\hat{i}|^2 = 1^2 = 1\)
- \(\hat{j} \cdot \hat{j} = |\hat{j}|^2 = 1^2 = 1\)
- \(\hat{k} \times \hat{k} = 0\) (cross product of a vector with itself is always the zero vector)
Step 2: Substitute these values into the expression.
\[
\hat{i} \cdot \hat{i} - \hat{j} \cdot \hat{j} + \hat{k} \times \hat{k} = 1 - 1 + 0
\]
Step 3: Simplify.
\[
1 - 1 + 0 = 0
\]
Step 4: Conclusion.
The value of the given expression is 0.
Final Answer: (A) 0