Let's Assume the sum of \(n\) consecutive natural number cubes be \([\frac{n(n + 1)}{2}]^2\)
The sum of \(n\) consecutive natural numbers be \(\frac{n(n + 1)}{2}\)
The Expression given = \((1^3 + 2^3 + 3^3 + ......... + 15^3)\) - \((1 + 2 + 3 + ......... + 15)\)
= From the above = \([ \frac{15(15 + 1)}{2}]^2 - \frac{15 × 16}{2}\)
= \([\frac{15 × 16}{2}]^2 - \frac{15 × 16}{2}\)
= \((120)^2\) - 120
= 14400 - 120
= 14280
The correct option is (A): 14280
If pqr = 1 then
\((\)\((\frac{1}{1 + p + q^-1})\) \(+\) \((\frac{1}{1 + q + r^-1})\) \(+\) \((\frac{1}{1 + r + p^-1})\)\()\) is equal to