The first law of thermodynamics gives: \[ dQ = du + dW \]
At constant pressure, this becomes: \[ C dT = C_v dT + P dV \tag{1} \]
Given \( PV^2 = RT \), differentiating both sides with respect to \( T \) at constant \( P \): \[ P(2V dV) = R dT \] \[ P dV = \frac{R}{2V} dT \]
Substitute \( P dV \) into equation (1): \[ C dT = C_v dT + \frac{R}{2V} dT \] \[ C = C_v + \frac{R}{2V} \]
Thus, the specific heat at constant pressure is: \[ C = C_v + \frac{R}{2V}. \]
A body of mass 1000 kg is moving horizontally with a velocity of 6 m/s. If 200 kg extra mass is added, the final velocity (in m/s) is: