Concept:
• The constraints \(x \ge 0, y \ge 0\) restrict the feasible region to the first quadrant.
• For each inequation, plot the corresponding line and determine which side represents the inequality by testing a point (usually the origin \((0,0)\)).
• An unbounded region extends infinitely in at least one direction.
Step 1: Analyze the first inequality \(3x + y \ge 3\)
Plot the line \(3x + y = 3\).
Intercepts: \(x\)-intercept \(= (1, 0)\), \(y\)-intercept \(= (0, 3)\).
Test \((0,0)\): \(3(0) + 0 \ge 3 \implies 0 \ge 3\) (False).
The region is on the side away from the origin.
Step 2: Analyze the second inequality \(2x - y \ge -5\)
Plot the line \(2x - y = -5\).
Intercepts: \(x\)-intercept \(= (-2.5, 0)\), \(y\)-intercept \(= (0, 5)\).
Test \((0,0)\): \(2(0) - 0 \ge -5 \implies 0 \ge -5\) (True).
The region is on the side towards the origin.
Step 3: Determine if the intersection is bounded
In the first quadrant (\(x, y \ge 0\)):
The region is bounded below by the line \(y = 3 - 3x\).
The region is bounded on the other side by the line \(y = 2x + 5\).
Note that as \(x\) increases towards infinity, both \(3x+y \ge 3\) and \(2x-y \ge -5\) can be satisfied simultaneously for large values of \(y\) (specifically, \(y\) can range between \(0\) and \(2x+5\)).
For example, the point \((100, 100)\) satisfies both:
\(3(100) + 100 = 400 \ge 3\)
\(2(100) - 100 = 100 \ge -5\)
Since there is no upper limit on how large \(x\) or \(y\) can be while staying in the first quadrant and satisfying these constraints, the region is unbounded.