Question:
The period of \( 2 \sin 4x \cos 4x \) is:
The period of \( 2 \sin 4x \cos 4x \) is:
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The period of a sine or cosine function is \( \frac{2\pi}{|A|} \) where \( A \) is the coefficient of \( x \).
Updated On: Apr 7, 2026
- \( \frac{2\pi}{3} \)
- \( \frac{2\pi}{4} \)
- \( \frac{\pi}{2} \)
- \( \frac{\pi}{4} \)
- \( \pi \)
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The Correct Option is D
Solution and Explanation
The period of \( \sin A \cos A \) is given by \( \frac{2\pi}{|A|} \).
Here, \( A = 4x \), so the period of \( 2 \sin 4x \cos 4x \) is: \[ \frac{2\pi}{4} = \frac{\pi}{4} \] Thus, the correct answer is \( \frac{\pi}{4} \).
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