




A NAND gate produces an output that is the negation of the AND gate output. The output (\( Y \)) is given by: \[ Y = \overline{A \cdot B}, \] where \( A \) and \( B \) are the inputs to the NAND gate. The truth table for a NAND gate is as follows:

Step-by-Step Analysis of the Inputs and Outputs: - When both \( A = 0 \) and \( B = 0 \), the output \( Y = 1 \).
- When \( A = 0 \) and \( B = 1 \), the output \( Y = 1 \). - When \( A = 1 \) and \( B = 0 \), the output \( Y = 1 \).
- When both \( A = 1 \) and \( B = 1 \), the output \( Y = 0 \).
Now analyze the given input waveforms for \( A \) and \( B \):
1. For each interval where \( A \) and \( B \) are given, calculate \( A \cdot B \).
2. Take the negation (\( \overline{A \cdot B} \)) to find the output \( Y \).
From the given inputs and truth table, the output waveform matches Option (2).

An infinitely long straight wire carrying current $I$ is bent in a planar shape as shown in the diagram. The radius of the circular part is $r$. The magnetic field at the centre $O$ of the circular loop is :





Which of the following circuits has the same output as that of the given circuit?

Consider the following reaction sequence.

Foot of perpendicular from origin on a line passing through $(1, 1, 1)$ having direction ratios $\langle 2, 3, 4 \rangle$, is: