Question:

The order and degree of differential equation \( \frac{d^2y}{dx^2} = 1 - \left( \frac{d^3y}{dx^3} \right)^2 \) is :

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Always locate the highest derivative first to find the order. The degree belongs exclusively to that specific term's exponent, regardless of how high other lower-derivative powers are.
  • Order = 3, Degree = 3
  • Order = 2, Degree = 2
  • Order = 3, Degree = 2
  • Order = 2, Degree = 1
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The Correct Option is C

Solution and Explanation

Concept:
Order: The order of a differential equation is defined as the highest derivative order present anywhere inside the equation.
Degree: The degree is the power of the highest order derivative term, provided the differential equation is written as a polynomial expression in terms of its derivatives.

Step 1: Determine the order.
Look at the derivative components present in the given equation: \[ \frac{d^2y}{dx^2} \quad \text{(Second derivative)} \] \[ \frac{d^3y}{dx^3} \quad \text{(Third derivative)} \] The highest derivative order appearing in the expression is \( 3 \). Thus, Order = 3.

Step 2: Determine the degree.
Identify the term containing this highest derivative, which is \( \left( \frac{d^3y}{dx^3} \right)^2 \). The exponent power of this term is \( 2 \). Since the entire equation is a polynomial in derivatives, the degree is simply this exponent. Thus, Degree = 2.
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