Question:
The number of segregating genes in a cross between two inbreds, if the F$_2$ population has 256 individuals, is
The number of segregating genes in a cross between two inbreds, if the F$_2$ population has 256 individuals, is
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Segregation in F$_2$:
- F$_2$ population size = 4$^n$ (for complete dominance).
- Number of phenotypic classes = 2$^n$.
- Used to estimate the number of genes controlling a trait.
- F$_2$ population size = 4$^n$ (for complete dominance).
- Number of phenotypic classes = 2$^n$.
- Used to estimate the number of genes controlling a trait.
Updated On: Sep 1, 2026
- 4
- 9
- 16
- 8
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Question:
This question tests knowledge of segregation ratios in F$_2$ populations.
Step 2: Key Formula or Approach:
The number of segregating genes (n) can be calculated from the number of F$_2$ individuals (or F$_2$ population size) if the ratio is known.
The formula is: $4^n = \text{Number of F$_2$ individuals}$.
Step 3: Detailed Explanation:
Given: F$_2$ population size = 256.
$4^n = 256 \Rightarrow 4^n = 4^4 \Rightarrow n = 4$.
Thus, there are 4 segregating genes.
9 (B): Not correct.
16 (C): Not correct.
8 (D): Not correct.
Final Answer:
Thus, the number of segregating genes is 4, which corresponds to option (A).
[0.5cm]
This question tests knowledge of segregation ratios in F$_2$ populations.
Step 2: Key Formula or Approach:
The number of segregating genes (n) can be calculated from the number of F$_2$ individuals (or F$_2$ population size) if the ratio is known.
The formula is: $4^n = \text{Number of F$_2$ individuals}$.
Step 3: Detailed Explanation:
Given: F$_2$ population size = 256.
$4^n = 256 \Rightarrow 4^n = 4^4 \Rightarrow n = 4$.
Thus, there are 4 segregating genes.
9 (B): Not correct.
16 (C): Not correct.
8 (D): Not correct.
Final Answer:
Thus, the number of segregating genes is 4, which corresponds to option (A).
[0.5cm]
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