We are given the equation:
\[
|x + 1| |x + 3| - 4|x + 2| + 5 = 0
\]
Case 1: \(x \leq -3\)
Replacing all absolute values with negatives:
\[
(x + 1)(x + 3) + 4(x + 2) + 5 = 0
\]
Simplify:
\[
x^2 + 4x + 3 + 4x + 8 + 5 = 0
\]
\[
x^2 + 8x + 16 = 0
\]
\[
(x + 4)^2 = 0 \Rightarrow x = -4
\]
Case 2: \(-3 \leq x \leq -2\)
\[
-(x + 1)(x + 3) + 4(x + 2) + 5 = 0
\]
Simplify:
\[
-x^2 - 4x - 3 + 4x + 8 + 5 = 0
\]
\[
-x^2 + 10 = 0
\]
\[
x = \pm \sqrt{10}
\]
Since \(x \in [-3, -2]\), no valid root in this interval.
Case 3: \(-2 \leq x \leq -1\)
\[
-(x + 1)(x + 3) - 4(x + 2) + 5 = 0
\]
Simplify:
\[
-x^2 - 4x - 3 - 4x - 8 + 5 = 0
\]
\[
-x^2 - 8x - 6 = 0
\]
\[
x^2 + 8x + 6 = 0
\]
\[
x = \frac{-8 \pm \sqrt{64 - 24}}{2} = -4 \pm \sqrt{10}
\]
Case 4: \(x \geq -1\)
\[
(x + 1)(x + 3) - 4(x + 2) + 5 = 0
\]
Simplify:
\[
x^2 + 4x + 3 - 4x - 8 + 5 = 0
\]
\[
x^2 = 0 \Rightarrow x = 0
\]
Final Step:
Checking all valid roots, the solutions are \(x = -4\) and \(x = 0.\)
Hence, the number of solutions = 2.
Given equation:
\[|x + 1||x + 3| - 4|x + 2| + 5 = 0.\]
To solve this, we break it into different cases based on the values of \(x\) that change the absolute values:
Case 1: \(x \leq -3\)
\[(x + 1)(x + 3) + 4(x + 2) + 5 = 0.\]
Simplifying:
\[x^2 + 4x + 3 + 4x + 8 + 5 = 0 \implies x^2 + 8x + 16 = 0 \implies (x + 4)^2 = 0.\]
\[x = -4.\]
Case 2: \(-3<x \leq -2\)
\[-(x + 1)(x + 3) + 4(x + 2) + 5 = 0.\]
Simplifying:
\[-x^2 - 4x - 3 + 4x + 8 + 5 = 0 \implies -x^2 + 10 = 0 \implies x^2 = 10.\]
\[x = \pm \sqrt{10}.\]
Case 3: \(-2<x \leq -1\)
\[-(x + 1)(x + 3) - 4(x + 2) + 5 = 0.\]
Simplifying:
\[-x^2 - 4x - 3 - 4x - 8 + 5 = 0 \implies -x^2 - 8x - 6 = 0 \implies x^2 + 8x + 6 = 0.\]
Solving using the quadratic formula:
\[x = \frac{-8 \pm \sqrt{64 - 24}}{2} = \frac{-8 \pm \sqrt{40}}{2} = -4 \pm \sqrt{10}.\]
Case 4: \(x>-1\)
\[x^2 + 4x + 3 - 4x - 8 + 5 = 0.\]
Simplifying:
\[x^2 = 0 \implies x = 0.\]
The number of distinct real roots is:
Total Solutions = 2.
Answer: 2.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,