Question:

The imaginary part of \(\frac{1 - i\sqrt{3}}{1 + i\sqrt{3}}\) is

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To find imaginary part, first convert expression into $a+ib$ form.
Updated On: Apr 30, 2026
  • $-\frac{1}{2}$
  • $\frac{1}{2}$
  • $\frac{\sqrt{3}}{2}$
  • $-\frac{\sqrt{3}}{2}$
  • $\frac{\sqrt{3}}{4}$
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The Correct Option is D

Solution and Explanation

Concept: Convert to standard form using conjugate.

Step 1:
Multiply by conjugate
\[ \frac{1 - i\sqrt{3}}{1 + i\sqrt{3}} \cdot \frac{1 - i\sqrt{3}}{1 - i\sqrt{3}} \]

Step 2:
Simplify denominator
\[ 1 + 3 = 4 \]

Step 3:
Simplify numerator
\[ (1 - i\sqrt{3})^2 = 1 - 2i\sqrt{3} - 3 = -2 - 2i\sqrt{3} \] \[ = \frac{-2 - 2i\sqrt{3}}{4} = -\frac{1}{2} - \frac{\sqrt{3}}{2}i \]

Step 4:
Imaginary part
\[ -\frac{\sqrt{3}}{2} \] Final Conclusion:
Option (D)
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