Step 1: Classifying the differential equation.
The equation
\[ \frac{dy}{dx} = y \]
is a first-order differential equation where the dependent variable \(y\) and the independent variable \(x\) can be separated. Hence, it belongs to the category of separable differential equations.
Step 2: Separating variables.
Rearrange the equation so that all terms involving \(y\) are on one side and all terms involving \(x\) are on the other:
\[ \frac{1}{y}\,dy = dx \]
Step 3: Integrating both sides.
Integrate with respect to the appropriate variables:
\[ \int \frac{1}{y}\,dy = \int dx \]
This gives:
\[ \ln|y| = x + C \]
where \(C\) is the constant of integration.
Step 4: Expressing the solution explicitly.
Exponentiating both sides to remove the logarithm:
\[ |y| = e^{x+C} \]
The constant \(e^C\) can be replaced by a new arbitrary constant \(C\), giving:
\[ y = Ce^x \]
Step 5: Verifying with the options.
(A) \(y = x + C\): derivative is 1, not equal to \(y\).
(B) \(y = Ce^x\): derivative is \(Ce^x = y\), so it satisfies the equation.
(C) \(y = Cx\): derivative is constant \(C\).
(D) \(y = e^{Cx}\): not the general solution form.
Step 6: Final conclusion.
The general solution of the differential equation is:
\[ \boxed{y = Ce^x} \]
Let \( M \) be a \( 7 \times 7 \) matrix with entries in \( \mathbb{R} \) and having the characteristic polynomial \[ c_M(x) = (x - 1)^\alpha (x - 2)^\beta (x - 3)^2, \] where \( \alpha>\beta \). Let \( {rank}(M - I_7) = {rank}(M - 2I_7) = {rank}(M - 3I_7) = 5 \), where \( I_7 \) is the \( 7 \times 7 \) identity matrix.
If \( m_M(x) \) is the minimal polynomial of \( M \), then \( m_M(5) \) is equal to __________ (in integer).
Consider the system of ordinary differential equations \[ \frac{dX}{dt} = MX, \] where \( M \) is a \( 6 \times 6 \) skew-symmetric matrix with entries in \( \mathbb{R} \). Then, for this system, the origin is a stable critical point for