Instead of counting the visible faces arm by arm, we can count every face on every separate block first and then subtract the faces that get hidden wherever two blocks are glued together.
The object is built from 1 central cube, 6 "inner" cubes (one glued to each face of the central cube), 6 "middle" cubes (one glued onto each inner cube), and 6 square pyramids (one glued onto each middle cube), so 19 solid pieces in all.
If every piece were sitting apart on its own, a cube contributes 6 faces and a square pyramid contributes 5 faces (4 triangular sides plus its square base).
\[
\text{Total faces if separate} = 1(6) + 6(6) + 6(6) + 6(5) = 6 + 36 + 36 + 30 = 108
\]
Now count the glued joints. There are 6 joints between the central cube and the inner cubes, 6 joints between the inner cubes and the middle cubes, and 6 joints between the middle cubes and the pyramids, giving 18 joints in total.
Every joint hides exactly two faces, one from each of the two pieces that meet there, since the two glued faces sit flush against each other and can never be seen.
\[
\text{Hidden faces} = 18 \times 2 = 36
\]
Subtracting the hidden faces from the total gives the number of faces that remain exposed on the outside of the whole object.
\[
\text{Exposed surfaces} = 108 - 36 = 72
\]
So the correct answer is 72.