Question:

The current flowing through an inductor of self-inductance L is continuously increasing at constant rate. The variation of induced e.m.f. (e) verses $\text{dI}/\text{dt}$ is shown graphically by figure}

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Induced e.m.f. is zero if current is constant. If current increases at a constant rate, e.m.f. is a constant non-zero value.
Updated On: May 14, 2026
  • B
  • A
  • D
  • C
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The Correct Option is B

Solution and Explanation


Step 1: Concept

The magnitude of induced e.m.f. ($e$) in an inductor is proportional to the rate of change of current: $e = L \frac{dI}{dt}$.

Step 2: Meaning

This equation is in the form $y = mx$, where $e$ is $y$ and $\frac{dI}{dt}$ is $x$. $L$ represents the constant slope.

Step 3: Analysis

A linear relationship between $e$ and $\frac{dI}{dt}$ should be represented by a straight line passing through the origin.

Step 4: Conclusion

Graph A correctly represents this proportional relationship. Final Answer: (B)
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