
The corresponding logic gate for the given truth table is
Step 1: Understanding the given truth table.
The truth table shows that the output is 1 when either \( A \) or \( B \) is 1, but not both. This corresponds to the behavior of an XOR (exclusive OR) gate, which outputs 1 when exactly one of the inputs is 1, and 0 when both inputs are the same.
Step 2: Identifying the logic gate.
XOR gate outputs 1 when the inputs are different, and 0 when they are the same.
OR gate outputs 1 if either of the inputs is 1.
AND gate outputs 1 only when both inputs are 1.
NAND gate is the inverse of the AND gate, outputting 1 except when both inputs are 1.
Thus, the correct answer is
(A) XOR.
At 15 atm pressure, $ \text{NH}_3(g) $ is being heated in a closed container from 27°C to 347°C and as a result, it partially dissociates following the equation: $ 2\text{NH}_3(g) \rightleftharpoons \text{N}_2(g) + 3\text{H}_2(g) $ If the volume of the container remains constant and pressure increases to 50 atm, then calculate the percentage dissociation of $ \text{NH}_3(g) $
If equilibrium constant for the equation $ A_2 + B_2 \rightleftharpoons 2AB \quad \text{is} \, K_p, $ then find the equilibrium constant for the equation $ AB \rightleftharpoons \frac{1}{2} A_2 + \frac{1}{2} B_2. $
Consider the following reaction: $ \text{CO}(g) + \frac{1}{2} \text{O}_2(g) \rightarrow \text{CO}_2(g) $ At 27°C, the standard entropy change of the process becomes -0.094 kJ/mol·K. Moreover, standard free energies for the formation of $ \text{CO}_2(g) $ and $ \text{CO}(g) $ are -394.4 and -137.2 kJ/mol, respectively. Predict the nature of the above chemical reaction.