Question:
The average of 11 consecutive even numbers written in ascending order is 30. What is the average of the 3rd and the 10th number?
The average of 11 consecutive even numbers written in ascending order is 30. What is the average of the 3rd and the 10th number?
Updated On: Sep 16, 2026
- 29
- 30
- 31
- 33
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The Correct Option is C
Solution and Explanation
Concept:
Step 1: Find the middle (6th) term
For 11 consecutive even numbers, the average equals the 6th term.
So the 6th term = 30.
Step 2: Write out all 11 terms using steps of 2
Terms run from (30 - 10) to (30 + 10) in steps of 2:
20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40
Step 3: Identify the 3rd and 10th terms and average them
3rd term = 24, 10th term = 38
Average = (24 + 38)/2 = 62/2 = 31
Final Answer: 31
- In a set of consecutive even numbers, the average equals the middle term.
- With 11 terms, the 6th term is the exact middle term and equals the average.
- Once the middle term is known, all other terms can be written using steps of 2.
Step 1: Find the middle (6th) term
For 11 consecutive even numbers, the average equals the 6th term.
So the 6th term = 30.
Step 2: Write out all 11 terms using steps of 2
Terms run from (30 - 10) to (30 + 10) in steps of 2:
20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40
Step 3: Identify the 3rd and 10th terms and average them
3rd term = 24, 10th term = 38
Average = (24 + 38)/2 = 62/2 = 31
Final Answer: 31
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