Step 1: Understand the problem
We need to find the area of the region bounded by the curve y = x, the x-axis, and the vertical lines x = 0 and x = 2.
Step 2: Set up the integral for the area
The area under the curve y = x from x = 0 to x = 2 is given by the definite integral:
Area = ∫ from 0 to 2 of x dx
Step 3: Calculate the integral
The integral of x with respect to x is (x²)/2.
So, Area = [ (x²)/2 ] evaluated from 0 to 2.
Step 4: Evaluate the definite integral
Substitute the upper limit x = 2:
(2)² / 2 = 4 / 2 = 2
Substitute the lower limit x = 0:
(0)² / 2 = 0
So, Area = 2 - 0 = 2 square units.
Step 5: Conclusion
The area of the region bounded by the curve y = x, the x-axis, x = 0 and x = 2 is 2 square units.
Final Answer: (C) 2
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.