Question:

The amplitude of $(1+i)^5$ is

Updated On: Jul 29, 2024
  • $\frac {3 \pi}{4}$
  • $\frac {-3 \pi}{4}$
  • $\frac {-5 \pi}{4}$
  • $\frac {5 \pi}{4}$
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The Correct Option is D

Solution and Explanation

Given, $\left(1 + i\right)^{5} $
$ = \left(\sqrt{2}\right)^{5} \left(\frac{1}{\sqrt{2}} + \frac{i}{\sqrt{2}}\right)^{5} $
$ = \left(\sqrt{2}\right)^{5} \left(\cos \frac{\pi}{4} +i \sin \frac{\pi}{4}\right)^{5} $
$ = \left(\sqrt{2}\right)^{5} \left(\cos \frac{5 \pi}{4} + i \sin \frac{5\pi}{4}\right) $
[by De-Moivre?s theorem]
Now, amplitude $ = \tan^{-1} \left(\frac{y}{x}\right) $
$= \tan^{-1} \left(\frac{\sin 5\pi /4}{\cos 5 \pi /4}\right) = \frac{5\pi}{4} $
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Concepts Used:

Argand Plane

It is a set of 3 mutually perpendicular axes and a convenient way to represent a set of numbers (2 or 3) or a point in space.

Argand Plane

Hence, we have a way to represent an imaginary number graphically. All we need to do is to find the real part and an imaginary part of it. Then, represent them on the two mutually perpendicular number lines. The point of intersection, as shown in the above diagram, is the origin of our Plane.

The formation of the Plane so formed is known as the Argand Plane and it is a convenient way to represent an imaginary number graphically.