Question:

The all values of z, such that
√2 sin z = coshβ + isinħβ, where β is real, are

Updated On: Sep 22, 2024
  • \(z=(2n+1)\frac{\pi}{2}+(-1)^n(\frac{\pi}{4}+i\beta), n=0,\pm1,\pm2,.......\)
  • \(z=n\pi-(-1)^n(\frac{3\pi}{4}+i\beta), n=0,\pm1,\pm2,.......\)
  • \(z=n\pi+(-1)^n(\frac{\pi}{4}+i\beta), n=0,\pm1,\pm2,.......\)
  • \(z=(2n+1)\frac{\pi}{2}+(-1)^n(\frac{\pi}{2}+i\beta), n=0,\pm1,\pm2,.......\)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

The correct answer is(C): \(z=n\pi+(-1)^n(\frac{\pi}{4}+i\beta), n=0,\pm1,\pm2,.......\)
Was this answer helpful?
0
1