\(x+7-\frac{8x}{3}=\frac{17}{6}-\frac{5x}{2}\)
L.C.M. of the denominators, \(2, 3\), and \(6\), is \(6\).
Multiplying both sides by \(6\), we obtain
\(6x + 42 - 16x = 17 - 15x\)
\(\Rightarrow\) \(6x - 16x + 15x = 17 - 42\)
\(\Rightarrow\) \(5x = - 25\)
\(\Rightarrow\) \(x\) = \(\frac{-25}{5}\)
\(\Rightarrow\) \(x\) = \(-5\)