Step 1: Understanding the Question:
The question asks for the biochemical reason why RNA molecules are much less stable than DNA molecules when exposed to high $pH$ (alkaline) environments.
This stability difference is fundamental to their biological roles (DNA as stable storage, RNA as a dynamic messenger).
Step 2: Detailed Explanation:
• Structural Difference in Pentose Sugars: DNA contains deoxyribose, which lacks an oxygen atom at the $2'$ position ($2'-H$). RNA contains ribose, which has a hydroxyl group at the $2'$ position ($2'-OH$).
• The Role of Alkali ($OH^-$ ions): In a basic solution, the concentration of hydroxide ions is high. These ions act as a base and deprotonate the $2'-OH$ group of the ribose sugar in RNA.
• Nucleophilic Attack: Once the $2'-OH$ is deprotonated to form a $2'-O^-$ (alkoxide ion), it becomes a potent nucleophile. This negatively charged oxygen performs an "intramolecular nucleophilic attack" on the adjacent phosphorus atom in the phosphodiester bond.
• Cyclic Intermediate Formation: This attack results in the formation of a $2',3'$-cyclic phosphate intermediate. In the process, the $5'$-phosphodiester linkage to the next nucleotide is broken.
• Cleavage of the Backbone: The cyclic intermediate is then hydrolyzed further into either $2'$- or $3'$-monophosphates, but the primary result is the total fragmentation of the RNA chain.
• Why DNA is Stable: Since DNA lacks the $2'-OH$ group, it cannot form this cyclic intermediate. Therefore, the DNA backbone remains intact and resistant to alkaline hydrolysis for long periods.
Step 3: Final Answer:
The presence of the $2'$-hydroxyl group in ribose makes RNA chemically unstable in alkaline conditions by facilitating a self-cleavage reaction of the phosphodiester bonds.