Let's break the problem down step by step.
Let \( r \) be the rate at which Mira walks and \( a \) be the rate at which Amal walks. Let the circumference of the circular track be \( C \).
1) Walking in the same direction:
In 46 minutes, the relative distance covered by Amal with respect to Mira (since they're moving in the same direction) is equivalent to 3 rounds.
So, \( 46(a - r) = 3C \)
From this, \( a - r = \frac{3C}{46} \)
2) Walking in opposite directions:
When moving in opposite directions, their relative speed gets added.
So, in 3 minutes, they've covered a distance equivalent to the circumference of the track (because they meet after Amal has walked a full circle more than Mira).
This means \( 3(a + r) = C \)
From this, \( a + r = \frac{C}{3} \) ... (ii)
Now, summing equations (i) and (ii):
\( 2a = \frac{3C}{46} + \frac{C}{3} \)
To get Mira's speed, subtract (i) from (ii):
\( 2r = \frac{C}{3} - \frac{3C}{46} \)
\( r = \frac{C}{6} - \frac{3C}{92} \)
\( r = \frac{11C}{46} \)
This means Mira covers a distance equivalent to \(\frac{11}{46}\) of the track in one minute.
In 60 minutes (1 hour), she covers \( \frac{11 \times 60}{46} = 14.35 \) times the circumference of the track.
So, Mira walks 14 rounds in one hour (because we'll only consider the complete rounds).