Question

Match the following:

• A. A-II, B-IV, C-III, D-I, E-V
• B. A-I, B-III, C-II, D-V, E-IV
• C. A-III, B-IV, C-V, D-I, E-II
• D. A-V, B-IV, C-III, D-II, E-I

Hint:

FCC metals are more ductile due to multiple slip systems compared to BCC and HCP.

Answer 1

The Correct Option is C

Concept: Metals crystallize in specific lattice structures depending on atomic packing efficiency, electronic configuration, and bonding nature. Common crystal structures:
• FCC → high packing density, ductile metals
• BCC → strong but less ductile
• HCP → limited slip systems, moderate ductility

Step 1: Identify crystal structures.

• Molybdenum → BCC structure
• Silver → FCC structure
• Titanium (α) → HCP structure
• Platinum → FCC structure
• Cadmium → HCP structure

Step 2: Match with given codes.
From standard crystallography data:
• A → BCC → III
• B → FCC → IV
• C → HCP → V
• D → FCC → I
• E → HCP → II Thus correct matching becomes: \[ A-III,\; B-IV,\; C-V,\; D-I,\; E-II \] Final Answer: \[ \boxed{\text{A-III, B-IV, C-V, D-I, E-II}} \]