Question:

Match List I with List II
Choose the correct answer from the options given below:

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Fatty Acid Shorthand: 18:0 = Stearic; 18:1 = Oleic; 18:2 = Linoleic; 18:3 = Linolenic; 20:4 = Arachidonic.
  • A - IV, B - I, C - V, D - II, E - III
  • A - III, B - V, C - I, D - IV, E - II
  • A - V, B - III, C - IV, D - I, E - II
  • A - II, B - IV, C - V, D - I, E - III
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The Correct Option is B

Solution and Explanation


Step 1: Understanding the Concept:

Standard biochemical lipid nomenclature designates carbon chain length and number of double bonds (C:D).
Key Formula or Approach:
\[ \text{Lipid Shorthand: } [\text{Number of Carbons}] : [\text{Number of Double Bonds}] \]

Step 2: Detailed Explanation:

Correlating shorthand notation with systematic fatty acid names:
- A. 18:0 (18 carbons, 0 double bonds, saturated) $\rightarrow$ III. Stearic acid.
- B. 18:1 (18 carbons, 1 double bond, monounsaturated $\omega$-9) $\rightarrow$ V. Oleic acid.
- C. 18:2 (18 carbons, 2 double bonds, polyunsaturated $\omega$-6) $\rightarrow$ I. Linoleic acid.
- D. 18:3 (18 carbons, 3 double bonds, polyunsaturated $\omega$-3) $\rightarrow$ IV. Linolenic acid.
- E. 20:4 (20 carbons, 4 double bonds, polyunsaturated $\omega$-6) $\rightarrow$ II. Arachidonic acid.
Matching sequence: A - III, B - V, C - I, D - IV, E - II.

Step 3: Final Answer:

Hence, the correct matching is A - III, B - V, C - I, D - IV, E - II, matching option (B).
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