Question:

Match List I (Clinical signs) with List II (Clinical description) and select the correct answer using the codes given below the lists.

List I (Clinical signs)List II (Clinical description)
A. Balance's sign1. Supraclavicular node in visceral malignancy
B. Kehr's sign2. Referred pain in left shoulder in splenic trauma
C. Cullen's sign3. Shifting dullness in flanks in splenic trauma
D. Trosier's sign4. Periumbilical discoloration in acute pancreatitis

Show Hint

Kehr's sign is shoulder pain, Cullen's sign is a belly button bruise, and Trosier's sign is a neck node from a hidden cancer.
Updated On: Jul 7, 2026
  • A-3, B-2, C-1, D-4
  • A-2, B-3, C-4, D-1
  • A-2, B-3, C-1, D-4
  • A-3, B-2, C-4, D-1
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

Step 1: Recall what each named sign stands for.
Balance's sign is fixed dullness felt in the left flank because of a walled off collection of blood around an injured spleen.
Kehr's sign is pain felt in the left shoulder tip when the spleen is injured, caused by blood irritating the diaphragm, which shares a nerve supply with the shoulder.
Cullen's sign is a bluish discoloration around the umbilicus, seen when blood tracks under the skin in severe haemorrhagic pancreatitis.
Trosier's sign (also written Troisier's sign) is an enlarged, hard lymph node above the left collar bone, a warning sign of a hidden abdominal or chest cancer, most often stomach cancer.

Step 2: Match each sign to its description in List II.
Balance's sign is about the flank finding in splenic trauma, so A matches 3.
Kehr's sign is about referred shoulder pain in splenic trauma, so B matches 2.
Cullen's sign is about periumbilical discoloration, linked here to pancreatitis, so C matches 4.
Trosier's sign is about a supraclavicular node from an internal cancer, so D matches 1.

Step 3: Put the matches together.
This gives A-3, B-2, C-4, D-1.

Step 4: Compare with the codes.
Code (a) gives A-3, B-2, C-1, D-4, which is wrong for C and D.
Code (b) gives A-2, B-3, C-4, D-1, which is wrong for A and B.
Code (c) gives A-2, B-3, C-1, D-4, which does not match our derived pairing.
Code (d) gives A-3, B-2, C-4, D-1, which matches our derived answer exactly.

Step 5: Final Answer:
The correct code is (d), that is A-3, B-2, C-4, D-1.
Was this answer helpful?
0
0