Question:

Let the tangent and normal at the point \((3\sqrt{3},1)\) on the ellipse \(\frac{ x^2}{36}+\frac{y^2}{4} =1\) meet the y-axis at the points A and B respectively. Let the circle C be drawn taking AB as a diameter and the line x = \(2\sqrt{5}\) intersect C at the points P and Q. If the tangents at the points P and Q on the circle intersect at the point (α,β) , then α2 - β2 is equal to 

Updated On: Apr 23, 2024
  • 60
  • 61
  • \(\frac{304}{5}\)
  • \(\frac{314}{5}\)
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The Correct Option is C

Solution and Explanation

The correct option is(C): \(\frac{304}{5}\)
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