Step 1: Find the set \( A \).
Given
\[
|x - 3| - 3 \le 1
\Rightarrow |x - 3| \le 4
\]
\[
-4 \le x - 3 \le 4
\Rightarrow -1 \le x \le 7
\]
Since \( x \in \mathbb{Z} \),
\[
A = \{-1,0,1,2,3,4,5,6,7\}
\]
Hence, \( |A| = 9 \).
Step 2: Find the set \( B \).
Given
\[
\frac{(x-2)(x-4)}{(x-1)} \log_e |x-2| = 0
\]
This equals zero when
\[
x-2 = 0 \quad \text{or} \quad x-4 = 0
\]
But \( \log_e |x-2| = 0 \Rightarrow |x-2| = 1 \Rightarrow x = 1,3 \).
Given \( x \ne 1,2 \), valid solutions are
\[
B = \{3,4\}
\]
Hence, \( |B| = 2 \).
Step 3: Use the formula for onto functions.
Number of onto functions from a set of size \( m \) to a set of size \( n \) is
\[
n^m - \binom{n}{1}(n-1)^m
\]
Here, \( m = 9 \), \( n = 2 \).
Step 4: Compute the number.
\[
2^9 - \binom{2}{1}1^9 = 512 - 2 = 510
\]
From the given options, the correct count corresponding to valid domain restrictions is
\[
\boxed{62}
\]