Let the mean and variance of the frequency distributionxi 2 4 6 8 10 12 14 16 fi 4 4 α 15 8 β 4 5
are 9 and 15.08 respectively, then the value of α2+β2-αβ is ____.
| xi | 2 | 4 | 6 | 8 | 10 | 12 | 14 | 16 |
| fi | 4 | 4 | α | 15 | 8 | β | 4 | 5 |
Correct Answer: 25
Solution and Explanation
We use the given values and apply the formula for mean and variance to find:
\[ N = \sum f_i = 40 + \alpha + \beta \] \[ \sum f_i x_i = 360 + 6\alpha + 12\beta \] \[ \sum f_i x_i^2 = 3904 + 36\alpha + 144\beta \] Mean (\(\overline{x}\)) is: \[ \overline{x} = \frac{\sum f_i x_i}{\sum f_i} = 9 \] From this, we have the equation: \[ 360 + 6\alpha + 12\beta = 9(40 + \alpha + \beta) \] Simplifying: \[ 360 + 6\alpha + 12\beta = 9(40 + \alpha + \beta) \quad \Rightarrow \quad 3\alpha = 3\beta \quad \Rightarrow \quad \alpha = \beta \] Next, we calculate the variance (\(\sigma^2\)): \[ \sigma^2 = \frac{\sum f_i x_i^2}{\sum f_i} - \left( \frac{\sum f_i x_i}{\sum f_i} \right)^2 \] Substituting the values: \[ \sigma^2 = \frac{3904 + 36\alpha + 144\beta}{40 + \alpha + \beta} - (9)^2 = 15.08 \] From this, we get: \[ 3904 + 36\alpha + 144\beta = (40 + \alpha + \beta)(9)^2 = 15.08 \] Solving this: \[ 3904 + 36\alpha + 144\beta = 360 + 180\alpha \] \[ 3904 + 36\alpha + 144\beta = 360 + 180\alpha \] Now solving for \(\alpha = 5\) and \(\beta = 2\), we find: \[ \alpha^2 + \beta^2 - \alpha\beta = 25 \]
"
Top JEE Main Mathematics Questions
- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.
- If , then the general value of is:
- The general solution of
- If the constant term in the binomial expansion of $\left(\frac{x^{\frac{3}{2}}}{2}-\frac{4}{x^l}\right)^9$ is $-84$ and the coefficient of $x^{-3 l}$ is $2^\alpha \beta$, where $\beta<0$ is an odd number, then $|\alpha l-\beta|$ is equal to_____
Top JEE Main Mean Deviation Questions
- Let \(a, b, c \in \mathbb{N}\) and \(a<b<c\). Let the mean, the mean deviation about the mean and the variance of the 5 observations \(9, 25, a, b, c\) be \(18, 4\) and \(\frac{136}{5}\), respectively. Then \(2a + b - c\) is equal to _______.
- Let the mean and variance of the observations \( 2, 3, 3, 4, 5, 7, a, b \) be 4 and 2, respectively. Then, the mean deviation about the mode of the observation is:
Let the mean and standard deviation of marks of class A of $100$ students be respectively $40$ and $\alpha$ (> 0 ), and the mean and standard deviation of marks of class B of $n$ students be respectively $55$ and 30 $-\alpha$. If the mean and variance of the marks of the combined class of $100+ n$ students are respectively $50$ and $350$ , then the sum of variances of classes $A$ and $B$ is :
- If the mean deviation about the mean of the numbers 1, 2, 3, …. n, where n is odd, is \(\frac{5(n + 1)}{n}\), then n is equal to ______.
Top JEE Main Questions
- Two masses $m$ and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$. The rod is suspended by a thin wire of torsional constant $k$ at the centre of mass of the rod-mass system(see figure). Because of torsional constant $k$, the restoring torque is $\tau =k\theta$ for angular displacement $\theta$. If the rod is rota ted by $\theta_0$ and released, the tension in it when it passes through its mean position will be:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,