Question:

Let $[t]$ denote the greatest integer less than or equal to $t$. Let $f: [0, \infty) \to \mathbb{R}$ be a function defined by \[ f(x) = \left[\frac{x}{2} + 3\right] - \left[\sqrt{x}\right]. \] Let $S$ be the set of all points in the interval $[0, 8]$ at which $f$ is not continuous. Then \[ \sum_{a \in S} a \] is equal to ________.

Updated On: Nov 26, 2024
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Correct Answer: 17

Solution and Explanation

\[\left\lfloor \frac{x}{2} + 3 \right\rfloor is  discontinuous  at  x = 2, 4, 6, 8\]
\[\sqrt{x} \text{ is discontinuous at } x = 1, 4\]
\[F(x) \text{ is discontinuous at } x = 1, 2, 6, 8\]
Summing the values:
\[\sum a = 1 + 2 + 6 + 8 = 17\]

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