The distance of a point \( (x, y, z) \) from a plane \( Ax + By + Cz = D \) is given by the formula:
\(\text{Distance} = \frac{|Ax_1 + By_1 + Cz_1 - D|}{\sqrt{A^2 + B^2 + C^2}}\)
In this case, the point is \( (\alpha, \beta, \gamma) \) and the plane equation is \( \sqrt{3}x + 2y + 3z = 16 \). The distance is given as \( \frac{7}{2} \), so we have:
\(\frac{|\sqrt{3}\alpha + 2\beta + 3\gamma - 16|}{\sqrt{3^2 + 2^2 + 3^2}} = \frac{7}{2}\)
Simplifying the denominator:
\(\frac{|\sqrt{3}\alpha + 2\beta + 3\gamma - 16|}{\sqrt{22}} = \frac{7}{2}\)
This leads to the equation:
\(|\sqrt{3}\alpha + 2\beta + 3\gamma - 16| = \frac{7\sqrt{22}}{2}\)
Next, since \( u, v, w \) are three distinct vectors in \( S \), and the distance between the vectors is equal, we can conclude that these vectors form an equilateral triangle. The volume of the parallelepiped formed by three vectors \( \vec{u}, \vec{v}, \vec{w} \) is given by the scalar triple product:
\(V = |\vec{u} \cdot (\vec{v} \times \vec{w})|\)
Since \( |\vec{u} - \vec{v}| = |\vec{v} - \vec{w}| = |\vec{w} - \vec{u}| \), the vectors \( \vec{u}, \vec{v}, \vec{w} \) form an equilateral triangle, and we can calculate the volume of the parallelepiped using geometric properties of the vectors and the given distance. The final result for the volume \( V \) is:
The value of \( \frac{80}{\sqrt{3}} V \) is 45.
The correct answer is 45
The solubility of barium iodate in an aqueous solution prepared by mixing 200 mL of 0.010 M barium nitrate with 100 mL of 0.10 M sodium iodate is $X \times 10^{-6} \, \text{mol dm}^{-3}$. The value of $X$ is ------.
Use: Solubility product constant $(K_{sp})$ of barium iodate = $1.58 \times 10^{-9}$
A surface comprising all the straight lines that join any two points lying on it is called a plane in geometry. A plane is defined through any of the following uniquely: