Question:

Let $f(x) = x^{4} - 4x^{3} + 4x^{2} +c, c \in \mathbb{R}.$ Then

Updated On: Apr 27, 2024
  • f(x) has infinitely many zeros in (1, 2) for all c
  • f(x) has exactly one zero in (1, 2) if -1 < c < 0
  • f(x) has double zeros in (1, 2) if -1 < c < 0
  • Whatever be the value of c, f(x) has no zero in (1, 2)
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The Correct Option is B

Solution and Explanation

$f\left(x\right) = x^{4} - 4x^{3} + 4x^{2} +c, c \in R$. Then $F'\left(x\right) = 4x^{3} - 12x^{2} + 8x = 4x \left(x^{2} - 3x + 2\right) = 4x\left(x - 1\right) \left(x - 2\right)$ if $-1 < c < 0$ $f\left(1\right) = 1 - 4 + 4 + c$ $= 1 + c > 0$ $f\left(2\right) = 16 - 32 + 16 + c$ $= c < 0$ $f\left(x\right)$ has exactly are zero in $\left(1, 2\right)$ if $-1 < c < 0$
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Concepts Used:

Functions

A function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output. Let A & B be any two non-empty sets, mapping from A to B will be a function only when every element in set A has one end only one image in set B.

Kinds of Functions

The different types of functions are - 

One to One Function: When elements of set A have a separate component of set B, we can determine that it is a one-to-one function. Besides, you can also call it injective.

Many to One Function: As the name suggests, here more than two elements in set A are mapped with one element in set B.

Moreover, if it happens that all the elements in set B have pre-images in set A, it is called an onto function or surjective function.

Also, if a function is both one-to-one and onto function, it is known as a bijective. This means, that all the elements of A are mapped with separate elements in B, and A holds a pre-image of elements of B.

Read More: Relations and Functions