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Let C be the circle in the complex plane with centre z0 =\(\frac{1}{2}\) (1+3i) and radius r = 1. Let z1 = 1+ i and the complex number z2 be outside the circle C such that |z1 – z0| |z2 – z0| = 1. If z0, z1 and z2 are collinear, then the smaller value of |z2|2 is equal to
Let C be the circle in the complex plane with centre z0 =\(\frac{1}{2}\) (1+3i) and radius r = 1. Let z1 = 1+ i and the complex number z2 be outside the circle C such that |z1 – z0| |z2 – z0| = 1. If z0, z1 and z2 are collinear, then the smaller value of |z2|2 is equal to
Updated On: Oct 3, 2024
- \(\frac{3}{2}\)
- \(\frac{5}{2}\)
- \(\frac{7}{2}\)
- \(\frac{13}{2}\)
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The Correct Option is B
Solution and Explanation
The correct option is(B): \(\frac{5}{2}\)
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