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Question:
Let a1 , a2 , a3 , a4 , a5 be a sequence of five consecutive odd numbers. Consider a new sequence of five consecutive even numbers ending with 2a3.
If the sum of the numbers in the new sequence is 450, then a5 is
Let a1 , a2 , a3 , a4 , a5 be a sequence of five consecutive odd numbers. Consider a new sequence of five consecutive even numbers ending with 2a3.
If the sum of the numbers in the new sequence is 450, then a5 is
If the sum of the numbers in the new sequence is 450, then a5 is
Updated On: Sep 26, 2024
- 81
- 41
- 61
- 51
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The Correct Option is D
Solution and Explanation
The 5 consecutive odd numbers are
a1 , a2 , a3 , a4 , a5
The 5 consecutive even numbers are
2a3 – 8, 2a3 – 6, 2a3 – 4, 2a3 – 2, 2a3
The sum of these 5 numbers = 10a3 – 20 = 450 (given)
∴ a3 = 47 and a5 = 51.
Ans: (51)
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