Concept:
Matrix addition is performed by adding the corresponding elements of the matrices.
If \[ A+B+C=O, \] then: \[ C=-(A+B) \]
Step 1: Calculate \(A+B\)
Given: \[ A= \begin{bmatrix} 0 & -3 & 4 \\ 1 & 0 & 2 \end{bmatrix} \] and \[ B= \begin{bmatrix} -3 & 0 & 1 \\ 2 & 4 & 0 \end{bmatrix} \] Adding corresponding elements: \[ A+B= \begin{bmatrix} 0+(-3) & -3+0 & 4+1 \\ 1+2 & 0+4 & 2+0 \end{bmatrix} \] \[ A+B= \begin{bmatrix} -3 & -3 & 5 \\ 3 & 4 & 2 \end{bmatrix} \]
Step 2: Find matrix \(C\)
Since: \[ A+B+C=O \] Therefore: \[ C=-(A+B) \] \[ C=- \begin{bmatrix} -3 & -3 & 5 \\ 3 & 4 & 2 \end{bmatrix} \] \[ C= \begin{bmatrix} 3 & 3 & -5 \\ -3 & -4 & -2 \end{bmatrix} \]
Step 3: Compare with the options
The required matrix is: \[ C= \begin{bmatrix} 3 & 3 & -5 \\ -3 & -4 & -2 \end{bmatrix} \]
Final Answer:
\[ \boxed{ C= \begin{bmatrix} 3 & 3 & -5 \\ -3 & -4 & -2 \end{bmatrix} } \] Hence, the correct answer is Option (C).
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.