Question

$K_m$ and $V_{max}$ of an enzyme preparation are 5 µM and 30 $µM min^{-1}$ respectively. Considering, $K_i$ value of competitive inhibitor is 60 µM, the velocity ($V_0$) of this enzyme-catalyzed reaction in the presence of 200 µM of substrate and 600 µM of competitive inhibitor is _______ $ µM min^{-1}$ (rounded off to two decimal places).

Answer 1

Correct Answer: 23.5

The Correct answer is : 23.50