Concept:
• Use trigonometric identity: \( 1 + \cos 2x = 2\cos^2 x \).
• Standard Integral: \( \int \sec x \, dx = \log |\sec x + \tan x| + C \).
Step 1: Simplify the integrand using trig identities
Let \( I = \int \frac{1}{\sqrt{1 + \cos 2x}} \, dx \).
Substitute \( 1 + \cos 2x = 2\cos^2 x \):
\[ I = \int \frac{1}{\sqrt{2\cos^2 x}} \, dx \]
\[ I = \int \frac{1}{\sqrt{2} \cos x} \, dx \]
Step 2: Transform the integral into a standard form
Factor out the constant \( 1/\sqrt{2} \):
\[ I = \frac{1}{\sqrt{2}} \int \frac{1}{\cos x} \, dx \]
\[ I = \frac{1}{\sqrt{2}} \int \sec x \, dx \]
Step 3: Integrate and add the constant of integration
Applying the standard formula for \( \int \sec x \, dx \):
\[ I = \frac{1}{\sqrt{2}} \log |\sec x + \tan x| + C \]
This result matches option (B).