Question:
In \(\triangle ABC\), \(AB = 17.5\) cm, \(AC = 9\) cm. Let \(D\) be a point on \(BC\) such that \(AD \perp BC\) and \(AD = 3\) cm. What is the radius of the circumcircle of \(\triangle ABC\)?
In \(\triangle ABC\), \(AB = 17.5\) cm, \(AC = 9\) cm. Let \(D\) be a point on \(BC\) such that \(AD \perp BC\) and \(AD = 3\) cm. What is the radius of the circumcircle of \(\triangle ABC\)?
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Circumradius formula \(R = \frac{abc}{4\Delta}\) is often the fastest way if all sides are known.
Updated On: Jul 30, 2025
- 17.05
- 27.85
- 22.45
- 32.25
- 26.25
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The Correct Option is C
Solution and Explanation
Area = \(\frac12 \times BC \times AD\).
Using cosine rule, find \(BC\) and then \( \text{Area} \).
Circumradius formula: \(R = \frac{abc}{4\Delta}\).
This yields \(R \approx 22.45\) cm.
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