To Prove: BC || QR
Proof:
In ∆ POQ, AB || PQ
∴\(\frac{OA}{AP}=\frac{OB}{BQ}\)............(i)
In ∆ POR, AC||PR
∴\(\frac{OA}{AP}=\frac{OC}{CR}\)...........(ii)
From (i) and (ii) we obtain,
\(\frac{OB}{BQ}=\frac{OC}{CR}\)
∴ BC || QR
(By the converse of the basic proportionality theorem)
Hence Proved