Concept:
- When certain letters must always stay together, tie them into a single block and arrange this block along with the remaining letters.
- Multiply by the number of ways to arrange the letters within that block.
- Divide by the factorial of the count of each repeated letter to avoid overcounting identical arrangements.
Step 1: List the letters of 'EMBROIDERY' and separate vowels from consonants
Letters: E, M, B, R, O, I, D, E, R, Y (10 letters total)
Vowels: E, O, I, E → 4 vowels (E repeats twice)
Consonants: M, B, R, D, R, Y → 6 consonants (R repeats twice)
Step 2: Treat all 4 vowels as a single block and arrange the units
Units to arrange = 6 consonants + 1 vowel-block = 7 units
Since R repeats twice among the consonants, arrangements of these 7 units = 7!/2! = 5040/2 = 2520
Step 3: Arrange the vowels within their block
Vowels are E, E, I, O (E repeats twice)
Arrangements within block = 4!/2! = 24/2 = 12
Step 4: Multiply the two results
Total arrangements = 2520 x 12 = 30,240
Final Answer: 30,240