Question:

In how many different ways can the letter of the word 'EMBROIDERY' be arranged so that all vowels are always positioned together?

Updated On: Sep 16, 2026
  • 1,20,960
  • 8,640
  • 4,320
  • 30,240
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The Correct Option is D

Solution and Explanation

Concept:
  • When certain letters must always stay together, tie them into a single block and arrange this block along with the remaining letters.
  • Multiply by the number of ways to arrange the letters within that block.
  • Divide by the factorial of the count of each repeated letter to avoid overcounting identical arrangements.

Step 1: List the letters of 'EMBROIDERY' and separate vowels from consonants
Letters: E, M, B, R, O, I, D, E, R, Y (10 letters total)
Vowels: E, O, I, E → 4 vowels (E repeats twice)
Consonants: M, B, R, D, R, Y → 6 consonants (R repeats twice)

Step 2: Treat all 4 vowels as a single block and arrange the units
Units to arrange = 6 consonants + 1 vowel-block = 7 units
Since R repeats twice among the consonants, arrangements of these 7 units = 7!/2! = 5040/2 = 2520

Step 3: Arrange the vowels within their block
Vowels are E, E, I, O (E repeats twice)
Arrangements within block = 4!/2! = 24/2 = 12

Step 4: Multiply the two results
Total arrangements = 2520 x 12 = 30,240

Final Answer: 30,240
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