Question:

In an experiment to measure the speed of sound by a resonating air column, a tuning fork of frequency $500 \, Hz$ is used. The length of the air column is varied by changing the level of water in the resonance tube. Two successive resonances are heard at air columns of length $50.7 \, cm $ and $83.9 \, cm$. Which of the following statements is (are) true?

Updated On: Jun 14, 2022
  • The speed of sound determined from this experiment is $332 \, m \, s^{-1}$
  • The end correction in this experiment is $0.9 \, cm$
  • The wavelength of the sound wave is $66.4 \, cm $
  • The resonance at $50.7 \, cm $ corresponds to the fundamental harmonic
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The Correct Option is C

Solution and Explanation

Let - $n_1$ harmonic is corresponding to 50.7 cm & $n_2$ harmonic is corresponding 83.9 cm.
sinc both one consecutive harmonics.
$\therefore$ their difference $= \frac{\lambda}{2}$
$\therefore \, \frac{\lambda}{2} = (83.9 - 50.7) cm $
$\frac{\lambda}{2} = 33.2 \, cm . $
$\lambda = 66.4 \, cm $
$\therefore \, \frac{\lambda}{4} = 16.6 cm $
length corresponding to fundamental mode must be close to $\frac{\lambda}{4} \& \, 50.7 \, cm$ must be an odd multiple of this length $16.6 \times 3 = 49.8 cm$. therefore 50.7 is 3rd harmonic
If end correction is e, then
$e + 50.7 = \frac{3 \lambda}{4}$
$e = 49.8 - 50.7 = - 0.9 \, cm $
speed of sound, $v = f \lambda$
$\therefore \, \, v = 500 \times 66.4 \, cm/ \sec = 332.000 \, m/s $
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