Question:

In an electromagnetic wave, the magnitude of electric and magnetic fields are 100 V/m and 0.265 A/m. The maximum energy flow is

Updated On: Sep 27, 2024
  • (A) 26.5 W/m2
  • (B) 36.5 W/m2
     

  • (C) 46.7 W/m2
     

  • (D) 765 W/m2
     

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The Correct Option is A

Approach Solution - 1

Explanation:
Given:Electrical field E = 100 V/mMagnetic field B = 0.265 A/mThe energy flow is given by the Poynting vector S=E×BS=EBsinS=EB[=90, as E and B are perpendicular to each other]S=100V/m×0.265A/mS=26.5W/m2Hence, the correct option is (A).
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Approach Solution -2

The mutually perpendicular time-varying electric and magnetic fields give rise to electromagnetic waves which propagate with the speed of light at a right angle to both electric and magnetic fields.

  • Radio waves, Microwaves, Visible light, and X-rays are examples of electromagnetic waves.
  • The wavelength of the different types of electromagnetic waves is different.
  • An oscillating charge is a source of electromagnetic waves.

Properties of Electromagnetic Waves

The followings are the properties of electromagnetic waves

  • They does require any material medium for their propagation.
  • They can propagate in a vacuum as well as in a medium.
  • Speed of electromagnetic waves in free space or vacuum is 3 x 108 m/s.
  • Speed of electromagnetic waves in a medium is given by v = 1/√(μ𝜖). Where μ and 𝜖 are the permeability and permittivity of the medium respectively.
  • They are transverse in nature.
  • They carry energy as they travel from one point to another point in space.
  • The average energy density of electromagnetic wave is given by Uav = (𝜖0E02)/2 = B02/2μ0
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