Given that, initially number of matches team has played =40
The number of matches won by team =30% of 40=\(\frac{30}{100}×40\)=12
Let the remaining matches be x.
The number of remaining matches won by team =60% of
\(x=\frac{60}{100}× x=0.06x\)
simplifies :
\(=12+1.2x=40+x\)
\(=0.2x=16\)
\(=x=\frac{16}{0.2}\)
\(x=80\)
When the team won 90% of the remaining matches.
Then, the number of remaining matches won by the team 90% of
\(80=\frac{90}{100}×80=72\)
The total number of matches won by the team in the tournament
\(=12+72=84\)
so, correct answer is: 84.
We know that out of the 40 matches that have been played, 30 have been won.
The overall win percentage is 50% if the last 60% of the matches are won.
Let 'x' be the total number of games to be played.
\(0.5 \times 40 + x = 0.3 \times 40 + 0.6 \times x\)
\(0.6x + 0.3 \times 40 = 0.5 \times (40 + x)\)
\(12 + 0.6x = 20 + 0.5x = 8x = 80\)
\(⇒ x = 80\)
After they won, 90% of what was left \(= 80(0.9) = 72 \)
Thus, 84 wins in total.