In a closed traverse PQRST the following data were collected in the field. What is the correct sum of deflection angles for this traverse?
Line Length (m) Bearing PQ 201.54 62°42' QR 189.68 154°54' RS 231.94 202°32' ST 272.55 281°44' TP 256.83 22°00'
In a closed traverse PQRST the following data were collected in the field. What is the correct sum of deflection angles for this traverse?
| Line | Length (m) | Bearing |
|---|---|---|
| PQ | 201.54 | 62°42' |
| QR | 189.68 | 154°54' |
| RS | 231.94 | 202°32' |
| ST | 272.55 | 281°44' |
| TP | 256.83 | 22°00' |
Show Hint
- $382^\circ00'$
- $360^\circ00'$
- $540^\circ00'$
- $723^\circ52'$
The Correct Option is B
Solution and Explanation
\[ \text{Sum of deflection angles} = (n - 2) \times 180^\circ \]
However, for a closed traverse, the sum of the deflection angles is always:
\[ \boxed{360^\circ} \] regardless of the internal turning directions (left or right). This rule is derived from the principle of angle summation in polygonal loops.
Since PQRST is a closed traverse with 5 sides, this principle still applies and the correct answer is:
\[ \boxed{360^\circ00'} \]
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