Question

In 1984–85 what percentage of total value of exports accounts for items related to food?

• A. 23%
• B. 29.2%
• C. 32%
• D. 22%
• A. Rs. 2580 crore
• B. Rs. 896 crore
• C. Rs. 1986 crore
• D. Rs. 1852 crore
• A. 39
• B. 46.18
• C. 7
• D. 31.6
• A. 296 crore
• B. 629 crore
• C. 2064 crore
• D. 1792 crore

Answer 1

The Correct Option is D

Step 1: Identify known data from table and statements
From the problem statement:
- Total value of exports in 1985–86 = Rs. 25800 crore.
- Food accounts for 23% of total in 1985–86.
- The 1985–86 food exports exceed the 1984–85 food exports by Rs. 1006 crore.
Step 2: Find food exports in 1985–86
Food exports in 1985–86 = \( 23% \) of 25800
= \( 0.23 \times 25800 \)
= Rs. \( 5934 \) crore.
Step 3: Find food exports in 1984–85
Given: 1985–86 food exports exceed 1984–85 food exports by Rs. 1006 crore.
Thus: 1984–85 food exports = \( 5934 - 1006 \)
= Rs. \( 4928 \) crore.
Step 4: Find total exports in 1984–85
From table: Total exports in 1984–85 = Rs. 22400 crore.
Step 5: Calculate percentage of total
Percentage = \( \frac{\text{Food exports 1984–85}}{\text{Total exports 1984–85}} \times 100 \)
= \( \frac{4928}{22400} \times 100 \)
= \( 22.0% \) exactly.
Step 6: Cross-check
If 22% of 22400 = 4928, then 4928 + 1006 = 5934 (which matches 1985–86 food value).
All checks confirm correctness.
Therefore, the answer is (d) 22%.

Answer 2

Step 1: Recall relation between manufactured articles (M) and raw material (R) in 1984–85
It is given: In 1984–85, value of M exceeds value of R by 100%.
That means: \( M = R + 100% \text{ of } R = 2R \).
Step 2: Express total exports in 1984–85
Total = Food + M + R.
From Q160: Food = Rs. 4928 crore.
M = \( 2R \).
Thus: \( 22400 = 4928 + 2R + R \)
\( 22400 = 4928 + 3R \).
Step 3: Solve for R
\( 3R = 22400 - 4928 = 17472 \).
\( R = \frac{17472}{3} = 5824 \) crore.
Step 4: Compare R with food
Difference = \( R - \text{Food} \)
= \( 5824 - 4928 = 896 \) crore.
Step 5: Cross-check
M = \( 2R = 11648 \). Total = \( 4928 + 11648 + 5824 = 22400 \) — matches given.
Thus, the answer is (b) Rs. 896 crore.

Answer 3

Step 1: 1985–86 raw material value
Given: In 1985–86, ratio of raw material to manufactured articles = 3:4.
Let raw = \( 3x \), manuf = \( 4x \).
Food in 1985–86 = Rs. 5934 crore.
Total = \( 3x + 4x + 5934 = 25800 \)
\( 7x = 25800 - 5934 = 19866 \).
\( x = 2838 \) crore.
Thus, raw = \( 3x = 8514 \) crore.
Step 2: 1984–85 raw material value
From Q161: R = 5824 crore.
Step 3: Calculate percentage less
Difference = \( 8514 - 5824 = 2690 \) crore.
Percent less = \( \frac{2690}{8514} \times 100 \approx 31.6% \).
Step 4: Cross-check
If 31.6% of 8514 = 2690, then 8514 - 2690 = 5824, which matches 1984–85 raw.
Thus, the answer is (d) 31.6%.

Answer 4

Step 1: Manufactured articles value in 1984–85
From Q161: R = 5824 crore, M = 2R = 11648 crore.
Step 2: Manufactured articles value in 1985–86
From Q162: manuf = \( 4x = 4 \times 2838 = 11352 \) crore.
Step 3: Find change
Change = \( 11352 - 11648 = -296 \) crore.
Negative value means decrease of Rs. 296 crore.
Step 4: Interpretation
The exports of manufactured articles actually fell slightly between 1984–85 and 1985–86, so if the question means “change” (including decrease), answer is 296 crore in magnitude.
Thus, the answer is (a) 296 crore decrease.