Given \( y = x^x \). Take natural log on both sides:
\[
\ln y = \ln(x^x) = x \ln x \quad \cdots (1)
\]
Step 2: Differentiate both sides using implicit differentiation.
Differentiate equation (1) with respect to \( x \):
\[
\frac{1}{y} \cdot \frac{dy}{dx} = \frac{d}{dx}(x \ln x) = \ln x + 1
\]
Step 3: Multiply both sides by \( y = x^x \).