Question:

If \(W_1,W_2\) are two subspaces of a vector space \(V(F)\), then \(L(W_1\cup W_2)=\)

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The span of the union of two subspaces is equal to the sum of the two subspaces.
  • \(W_1\cap W_2\)
  • \(W_1\cup W_2\)
  • \(W_1+W_2\)
  • \(W_1-W_2\)
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The Correct Option is C

Solution and Explanation

Concept:
Here \(L(W_1\cup W_2)\) means the linear span of the set \(W_1\cup W_2\). The sum of two subspaces is defined as \[ W_1+W_2=\{w_1+w_2:w_1\in W_1,\ w_2\in W_2\} \]

Step 1: Understand span of union.
The span of \[ W_1\cup W_2 \] contains all finite linear combinations of vectors from \(W_1\) and \(W_2\). Therefore, every vector in the span can be written as \[ w_1+w_2 \] where \[ w_1\in W_1,\qquad w_2\in W_2 \]

Step 2: Compare with sum of subspaces.
This is exactly the definition of \[ W_1+W_2 \] Therefore, \[ L(W_1\cup W_2)=W_1+W_2 \]

Step 3: Final answer.
\[ \boxed{W_1+W_2} \]
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