Concept:
Two non-zero vectors are perpendicular if and only if their dot product is zero: \[ \vec{a}\cdot\vec{b}=0 \]
Step 1: Apply the condition of perpendicularity
Since the vectors represent the perpendicular strips of a Red Cross sign: \[ \vec{a}\cdot\vec{b}=0 \]
Step 2: Calculate the dot product
Given: \[ \vec{a}=3\hat{i}+2\hat{j}+\lambda\hat{k} \] and \[ \vec{b}=2\hat{i}-4\hat{j}+5\hat{k} \] Therefore, \[ (3\hat{i}+2\hat{j}+\lambda\hat{k}) \cdot (2\hat{i}-4\hat{j}+5\hat{k})=0 \] \[ (3)(2)+(2)(-4)+(\lambda)(5)=0 \] \[ 6-8+5\lambda=0 \]
Step 3: Solve for \(\lambda\)
\[ -2+5\lambda=0 \] \[ 5\lambda=2 \] \[ \lambda=\frac{2}{5} \]
Final Answer:
Therefore, \[ \boxed{\lambda=\frac{2}{5}} \] Hence, the correct answer is Option (C).
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.