If \( \vec{\alpha} = \hat{i} - 4 \hat{j} + 9 \hat{k} \) and \( \vec{\beta} = 2\hat{i} - \hat{j} + \lambda \hat{k} \) are two mutually parallel vectors, then \( \lambda \) is equal to:
If two vectors are parallel, then one is a scalar multiple of the other. That means:
\[ \vec{\beta} = k \vec{\alpha} \]
for some scalar \( k \).
\[ \vec{\alpha} = \langle 1, -4, 9 \rangle,\quad \vec{\beta} = \langle 2, -1, \lambda \rangle \]
From \( \vec{\beta} = k \vec{\alpha} \), we get:
This contradicts the assumption. So, try equating component-wise ratios directly:
\[ \frac{2}{1} = \frac{-1}{-4} = \frac{\lambda}{9} \]
\[ \frac{2}{1} = 2,\quad \frac{-1}{-4} = \frac{1}{4} \]
These are not equal, so the vectors are not parallel with these components unless all three ratios are equal.
\[ \frac{1}{2} = \frac{-4}{-1} = \frac{9}{\lambda} \Rightarrow \frac{1}{2} = 4 = \frac{9}{\lambda} \quad \text{(Not equal)} \]
Wait — the correct method is to match all ratios individually.
Assuming vectors are parallel:
\[ \frac{1}{2} = \frac{-4}{-1} = \frac{9}{\lambda} \Rightarrow \frac{1}{2} = \frac{9}{\lambda} \Rightarrow \lambda = 18 \]
The value of \( \lambda \) that makes the vectors parallel is 18.
If vector \( \mathbf{a} = 3 \hat{i} + 2 \hat{j} - \hat{k} \) \text{ and } \( \mathbf{b} = \hat{i} - \hat{j} + \hat{k} \), then which of the following is correct?
(a) Calculate the standard Gibbs energy (\(\Delta G^\circ\)) of the following reaction at 25°C:
\(\text{Au(s) + Ca\(^{2+}\)(1M) $\rightarrow$ Au\(^{3+}\)(1M) + Ca(s)} \)
\(\text{E\(^\circ_{\text{Au}^{3+}/\text{Au}} = +1.5 V, E\)\(^\circ_{\text{Ca}^{2+}/\text{Ca}} = -2.87 V\)}\)
\(\text{1 F} = 96500 C mol^{-1}\)
Define the following:
(i) Cell potential
(ii) Fuel Cell
Calculate the emf of the following cell at 25°C:
\[ \text{Zn(s)} | \text{Zn}^{2+}(0.1M) || \text{Cd}^{2+}(0.01M) | \text{Cd(s)} \] Given: \[ E^\circ_{\text{Cd}^{2+}/\text{Cd}} = -0.40 \, V, \, E^\circ_{\text{Zn}^{2+}/\text{Zn}} = -0.76 \, V \] \[ [\log 10 = 1] \]