If there are 3 alphabets in the English series between the alphabets written against numbers 10 and 22, then how many alphabets are there between the alphabets written against numbers 18 and 22?
“$k$ alphabets between” two letters means a gap of $k+1$ in positions. Use $A=1,\dots,Z=26$ for quick checks.
Four
From Q42 setup: $10\!\to\!P$, $18\!\to\!N$. “Three alphabets between 10 and 22” means the letter at 22 is 4 positions away from $P$ (16th), so it must be \(L\) (12th) or \(T\) (20th). Since \(T\) is already at 14, choose \(22\!\to\!L\). Between \(N\) (14th) and \(L\) (12th) lies only \(M\). Hence the required count is \(\boxed{1}\).
From the earlier part of this arrangement, position 10 holds P (the 16th letter) and position 18 holds N (the 14th letter). We are told that 3 letters of the alphabet lie between the letters at positions 10 and 22, and we must find how many lie between the letters at positions 18 and 22.
So the letter at position 22 must be L (12th letter). Writing out the alphabet strip J-K-L-M-N, only M sits strictly between L and N.
Hence, the correct answer is One.
