Question:

If the maximum and minimum amplitudes of an amplitude modulated wave are 9 V and 3 V respectively, then the modulation index is

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Modulation index determines the quality of the signal. $\mu>1$ leads to distortion (over-modulation).
Updated On: Mar 31, 2026
  • 1/2
  • 3
  • 2
  • 1/3
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The Correct Option is A

Solution and Explanation

Step 1: Formula for Modulation Index:
The modulation index ($\mu$ or $m$) is given by: \[ \mu = \frac{A_{max} - A_{min}}{A_{max} + A_{min}} \] where $A_{max}$ is maximum amplitude and $A_{min}$ is minimum amplitude.
Step 2: Substitution and Calculation:
Given $A_{max} = 9$ V and $A_{min} = 3$ V. \[ \mu = \frac{9 - 3}{9 + 3} \] \[ \mu = \frac{6}{12} \] \[ \mu = \frac{1}{2} \]
Step 3: Final Answer:
The modulation index is 1/2 (or 0.5).
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