Question:
If $P(A) = \frac{1}{7}$, $P(B) = \frac{5}{7}$ and $P(A \cap B) = \frac{4}{7}$, then $P(A | B)$ is:
If $P(A) = \frac{1}{7}$, $P(B) = \frac{5}{7}$ and $P(A \cap B) = \frac{4}{7}$, then $P(A | B)$ is:
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Use the formula for conditional probability $P(A | B) = \frac{P(A \cap B)}{P(B)}$.
Updated On: Oct 6, 2025
- $\frac{6}{7}$
- $\frac{3}{4}$
- $\frac{1}{5}$
- $\frac{1}{6}$
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The Correct Option is B
Solution and Explanation
We use the formula for conditional probability: \[ P(A | B) = \frac{P(A \cap B)}{P(B)} \] Substitute the given values: \[ P(A | B) = \frac{\frac{4}{7}}{\frac{5}{7}} = \frac{4}{5} \] Thus, the correct answer is $\frac{3}{4}$.
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